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Соединение Юпитера со звездой 11525Т каталога HIPPARCOS 26-28 октября 1998 г

Касас Р., Оскос А., M. Sveshnikov

Transactions of IAA RAS, issue 4, 61–68 (1999)

Abstract

The results of processing the observations of relative positions of Galilean satellites and the HIPPARCOS 115257 star, obtained during of their close approachement in 1998 October 26–28 at Observatorio del Teide (Instituto de Astrofisica de Canarias, Spain) are given. Analysis of 1792 CCD measurements of differences of equatorial coordinates between satellites and the star is done. Under the suggestion that Lieske's theory (E15) of the motion of galilean satellites is exactly correct, the normal place for position of Jupiter at the mean epoch 1998 October 28.d06027 UTC is constructed. The comparison of obtained normal place and the DE403 ephemerides shows the following resudials: $\Delta\alpha=-0.024''\pm0.009''$, $\Delta\delta=-0.095''\pm0.010''$.

Citation

Text
RIS
Касас Р., Оскос А., M. Sveshnikov. Соединение Юпитера со звездой 11525Т каталога HIPPARCOS 26-28 октября 1998 г // Transactions of IAA RAS. — 1999. — Issue 4. — P. 61–68. TY - JOUR TI - Соединение Юпитера со звездой 11525Т каталога HIPPARCOS 26-28 октября 1998 г AU - Р., Касас AU - А., Оскос AU - Sveshnikov, M. PY - 1999 T2 - Transactions of IAA RAS IS - 4 SP - 61 AB - The results of processing the observations of relative positions of Galilean satellites and the HIPPARCOS 115257 star, obtained during of their close approachement in 1998 October 26–28 at Observatorio del Teide (Instituto de Astrofisica de Canarias, Spain) are given. Analysis of 1792 CCD measurements of differences of equatorial coordinates between satellites and the star is done. Under the suggestion that Lieske's theory (E15) of the motion of galilean satellites is exactly correct, the normal place for position of Jupiter at the mean epoch 1998 October 28.d06027 UTC is constructed. The comparison of obtained normal place and the DE403 ephemerides shows the following resudials: $\Delta\alpha=-0.024''\pm0.009''$, $\Delta\delta=-0.095''\pm0.010''$. UR - http://iaaras.ru/en/library/paper/230/ ER -